Correct Answer: Option D

Explanation

Force = Elastic constant x extension

Work done = \(\frac{1}{2} K \times e^2\)

Given Work done = 1.52J; Elastic constant (k) = ?; e = 40mm = 0.04 m

\(\therefore 1.52 = \frac{k \times (0.04)^2}{2}\)

\(3.04 = k \times 1.6 \times 10^{-3}\)

\(k = \frac{3.04}{1.6} \times 10^3\)

= 1.9 x 10\(^3\)

= 1900 Nm\(^{-1}\)

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