A ball of mass 0.1kg moving with a velocity of 20ms-1 is hit by a force which acts on it for 0.02s. If the ball moves off in the opposite direction with a velocity of 25ms-1 , calculate the magnitude of the force.

Mcdangenius

4 years ago

The answer is 225N what kind of thing is this!
In the opposite direction for schools sake!
Now take a chair, grab your pop corn and enjoy!
m=0.1kg
U=-20m/s
V= 25m/s
t=0.02 s
F=m(v-u)/t
=0.1(25-(-20)/0.02
0.1(25+20)/0.02
0.1(45)/0.02
4.5/0.02 =225N

Henriz

4 years ago

this Answer is 225N make corrections my school!!

MAMA_WOSA

3 years ago

BEEJAY'S TAKE 🪢🪢🪢

I pick 225 option D

Chimemeria

9 years ago

U guys should show Ur workings na

BethA1

2 years ago

all of you guys are confused ajeh!

MochiBaby

2 years ago

i clearly checked from my ALL INCLUSIVE CALCULATIONS IN PHYSICS and it said 25N

erianna

1 year ago

am confuse about the answer

glad4sure2010

5 years ago

F=m(v-u)/t
m=0.1kg
V=25mls
U=20mls
T=0.02sec
F=0.1(25-20)/0.02
F=0.1×5/0.02
F=25N

Motunrayo63

4 years ago

F=ma=m(v-u)/t
F=0.1(25-20)/0.02
F=0.1(5)/0.02
F=0.5/0.02
F=25N

Memunat33

4 years ago

Book learner workings🔥🔥🔥💥

Using Newtons second law of Motions

F= m{V—U}
----------
t


m=0.1kg
V=25mls
U=20mls
T=0.02sec
F=0.1(25-20)/0.02
F=0.1×5/0.02
F=25N🔥🔥✅✅

Speeeeed and accuracy 🔥🔥