30°
45°
60°
75°
90°
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Discussions (17)
Pls dis answer is wrong,d angle for maximum range is 45° but for maximum height it is 90°
The answer is option E not B. A projectile attain maximum height when the angle of projection is 90. Because Max height = U^2sin^2tita/2g
Sin 90° is 1. But when the angle is 45°, sin 45°= 0. 707. When you squared it, the answer is 0.5. So definitely the correct answer is 90°
It is clear you all are confused first off
maximum height is the highest vertical distance attained by a projectile when set in motion and the Range is the vertical distance covered by the projectile from the point of projection to where the projectile hits it's projection plane
Note: The question is clearly asking for the angle at which the maximum height attained is greatest not the range and the answer is 90
H = (Usin∅)²/2g
Sin ∅ is maximum when ∅ = 90⁰
Hence H is maximum when ∅ is 90⁰
A a launched projectile reaches its maximum height at 90 degrees not 45 degrees because at 90 degrees, the initial velocity of the projectile has no horizontal component. However, it covers a maximum range at 45 degrees
the answer showing is 90 but the correct answer ought to be 45. Kindly fix this discrepiancy
Whoever asked this question is an amateur in science. A complete joker.
There is no such thing as having a particular angle to attain maximum height. Each angle of projection has its own maximum height.
What can be asked in this context:
- Angle of inclination where max height occurs
- Angle of projection for maximum Range
- "Which of these angles" produce the greatest max height ? etc
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