Correct Answer: Option B

Explanation

The equation above is Beta-decay:
where β is an electron → \(^{0} _{-1}e\)

2β in the equation = \(^{0} _{-1}e\) + \(^{0} _{-1}e\) →  \(^{0} _{-2}e\)

\(^{222}_{86}Rn\) → \(^{x}_{88}Ra\) + \(^{0} _{-2}e\) + energy

where  \(^{x}_{88}Ra\) + \(^{0} _{-2}e\) → \(^{222}_{86}Rn\)

: x = 222 for element Radon [ \(^{222}_{88}Ra\)

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