A constant force acts on a body of mass 50kg and changes its speed from 20ms^-1 to 90ms^-1 in 10 seconds. Calculate the magnitude of the force applied.

munibae

9 years ago

Here is an explanation:

f=(mv-mu)/t

=((50×90)-(50×20))/10

=(4500-1000)/10

=3500/10

=350N

REF: New School Physics, page 176

Anibabasgee

3 years ago

force = mass*acceleration
speed=90-20=70
force= 50*70
=3500
applied force=force/time
applied force =3500/10=350N

zabeth256

2 months ago

f=ma. a=v-u/t
a=90-20/7. =7
m=50
f=ma
f=50*7=350N

A.y2009boi

1 year ago

change in displacement, (90-20) =70
acceleration=displacement/time
=70/10=7
f=ma
=50×7
350N
THANK YOU

zinchenckovic

2 months ago

90-20=70
50*70=3500
3500/10
=350N