Which of the following will reduce the frequency of oscillation of a simple pendulum?
Decreasing the length of the string
Increasing the amplitude of oscillation
Increasing the length of the string
Increasing the mass of the bob
Reducing the mass of the bob.
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When the known mass is added to the string and put into oscillation,it drags the mass downwards. But in a case the length of the string is/was increased it cause the string to force the pendulum to travel a greater distance to complete a cycle, taing more time or more period resulting in fewer oscillation per second (lower frequency). As we all know that Period T= 2pie * squareroot of (L/g). Where a longer L result in a longer T. And Frequency F= 1/T. That is, higher the value of T result to lower the value of L. I believe you understand it now. if no consult page 350-370 under Simple Harmonic Motion in New School Physics or Page 134-145 under Simple Harmonic Motion in Hidden Facts in Physics or Chapter 12 under Simple Harmonic motion in All Inclusive Physics

