An object of mass 5.0 cg moving with a velocity of 12ms^-1 due north hits a stationary body of mass 7.0kg. If they stick together after collision and move with velocity V due north, calculate the magnitude of V.

emmanuella.ahutu

5 years ago

For the explanation,
m1u1+m2u2=v(m1+m2)
m1=mass 1
u1=initial velocity of the first mass
m2=mass 2
u2=initial velocity of the second mass,=0(at rest)
v=final velocity, since the bodies coalesce
(5x12)+(7x0)=v(5+7)
60+0=5v+7v
60=12v
v=60/12
v=5

Yourstupid

3 years ago

The unit is in cg

Tobbysol

1 year ago

firstly, change 5cg to KGB
i.e 100cg is 1g
5cg to g is 5/100= 0.05g
now, g to KGB is 0.05/1000 = 0.00005kg
formula is:
M1V1 + M2V2 = V(M1+M2) (since they move in the same direction)
(0.00005*12)+(7*V2)=V2(7+0.00005)
0.0006+7V2=7V2+0.00005V2
0.0006=7.00005V2-7V2
0.0006=0.00005V2
V2=0.0006/0.00005
V2=12m/s

Emmykushy

2 years ago

Please find an answer