Calculate the magnitude of the force due to a magnetic field of 0.40T on an electron moving perpendicular to the field with a speed of 4.00 × 106ms^-1 (e 1.60 × 10^-19C]

6.40 × ^-10

6.40× 10^-13N

2.56 × 10^-13N

1.60 × 10^-12N

2.30 × 10^-11N

Correct Option

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9 years ago

Here is an explanation:

F=QVB

F=1.6*10^-19*4*10^6*0.4

F=2.56*10^-13N

REF: New School Physics, Page 428

9 years ago

F=QVB

F=1.6*10^-19*4*10^6*0.4

F=2.56*10^-13N

ceoofwahala

20th June, 2026

Chemistry

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20th June, 2026

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infinitehoaxx

21st May, 2026

Computer

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Calculate the magnitude of the force due to a magnetic field of 0.40T on an electron moving perpendicular to the field with a speed of 4.00 × 106ms-1 (e 1.60 × 10-19C]