A stone of mass 0.7 kg is projected vertically upward with a speed of 5 ms-1. Calculate the maximum height reached. [g =10ms^-2]

calekeys

5 years ago

Maximum height = U²/2g
=5²/2×10=1.25m

Chiboboskilala

1 year ago

squre root of 2*g*h=v
ur welcome!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Lola_fash

5 years ago

v=0 (when an object is thrown upwards its V=0)
u=5
g=10
h=?

the equation of motion will be = V^2=U^2-2gh
therefore, 0^2=5^2-2(10*h)
0=25-20h
20h=25
h=25/20
therefore h=1.25