Calculate the magnitude of the electric field intensity in a vacuum at a distance of 25cm from a charge of 5 × 10-3C. Take (\(\frac{1}{4πε0} = 9\times10^9Nm^2C^{-2}\))
Electric field intensity = \(\frac{q}{ 4πε₀r^2}\) r = 0.25m
= \(\frac{9 \times10^9 \times 5 \times 10^{-3}}{0.25^2}\)
= \(7.20 \times 10^8NC^{-1}\)
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