A voltage supply of 12V r.m.s. and frequency 90Hz is connected to a 4 ω resistor. Calculate the peak value of the current

Sesom31

5 years ago

Recall
I = V/R.
Peak current = V/R √2
V = 12
R = 4
Peak current = 12/4 √2
= 3√2
= 4.2

Award0001

2 years ago

you need to get the r.m.s current
ohms law (v = IR)
I = v/R = 12/4 = 3A(r.m.s)
rms current = peak current/√2
3 = Ip/√2
Ip = 3√2 = 4.2