A body is launched from the earth’s surface, of radius R, so that it just escapes from the gravitational influence of the earth; If the gravitational constant is G and the mass of the earth is M, what is the escape velocity of the boby.

a

\(\sqrt{2GM}\) ÷ R

b

\(\frac{\sqrt{2GM}}{R}\)

c

\(\frac{\sqrt{2G}}{MR}\)

d

\(\sqrt{2GMR}\)

e

\(\frac{\sqrt{R}}{2GM}\)

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Discussions (2)

Michaelimumoren
2 years ago

A and B say the same thing so both should be correct

malachisunday
2 years ago

what's the difference between A and B

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