Correct Answer: Option A

Explanation

Assume the two equal capacitors are 2 micro-farads respectively( you can assume any number)

Effective capacitor in series = \(\frac{1}{C_1} + \frac{1}{C_2}\)

                                             =  \(\frac{1}{2} + \frac{1}{2}\) = \(\frac{2}{2}\) = 1 micro-farads

Effective capacitance in parallel = \(C_1 + C_2\) =  2 + 2 = 4 micro-farads

The ratio of the effective series capacitance to the effective parallel capacitance  = 1: 4 = \(\frac{1}{4}\) = 0.25 

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