Calculate the amount of heat generated in an external load of resistance 8Ω if an alternating current of peak value 5 A is passed through it for 100s.

2.0 × 10⁴J

1.0 × 10⁴J

5.0 × 10³J

4.0 × 10³J

2.0 × 10²J

Correct Option

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1 year ago

The answer should be B. Convert the peak current to Irms

2 years ago

The ans is correct
Solution
E=I²RT
E=5²×8×100
E=2.0×10⁴
so A is correct

1 year ago

this should be B

peak Value is 5 therefore the RMS value will be 5/√2=3.546

H=I²RT

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