An air bubble of volume 4cm\(^3\) is formed 20m under water. What will be its volume when it rises to just below the surface of the water if the atmospheric pressure is equivalent to a height of 10m of water?

Champion26

3 years ago

(P+H)V¹=PV2
P=10cm
H=20m
V¹=4cm³
V2=?
V2[=(10+20)×4]/10
V2=12cm³

Wizifive

2 years ago

There is no answer in the options. Note 10cm and 20m you need to convert the units before adding them.

Cheriv7

1 year ago

Step 1: Define Initial Conditions
- Volume (V1) = 4 cm³
- Depth (h1) = 20 m
- Pressure (P1) = 20 m (water) + 10 m (atmospheric) = 30 m

Step 2: Define Final Conditions
- Depth (h2) = 0 m (surface)
- Pressure (P2) = 10 m (atmospheric pressure only, since water pressure is 0m at the surface)

Step 3: Apply Boyle's Law
P1V1 = P2V2
30 m x 4 cm³ = 10 m x V2

Step 4: Solve for V2
V2 = (30 m x 4 cm³) / 10 m
V2 = 12 cm³

The volume of the air bubble at the surface will be 12 cm³.

Somina4

3 weeks ago

according to the option given as answer I'll say that, that was supposed to be 10m not 10cm. But if the question actually says 10cm then the answer should be 804cm³