When a current of 1 .0A flows in an electrolyte for 3.0h, a mass of 1 .0g is deposited. What mass will be deposited in 10.0h if a current of 3.0A flows through the electrolyte?
a
30.0g
b
24.0g
c
10.0g
d
6.0g
e
0.4g
Explanation
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Primus113
5 years ago
C 

using
Q = it
whrre
Q = charge
i = current
t = time in sec
for M1
convert 3h to sec
60*60*3= 10800
for M2
convert 10h to sec
60*60*10 = 108000
if it takes 10800 current ti discharge 1g
how much will it take 108000
10800---->1
108000---x
= 108000/10800
=10

BossDave001
3 months ago
1st P=IT
P=1*3=3
3P=1.0g
2nd P=IT
P=3*10=30
3P=1.0g
30P=x
Cross multiply
X=30*1/3
X=10g
IQ🧠


