If the refractive index of water is 1.33, what is the critical angle for a water-air boundary?

Izzy15

6 years ago

sin c= 1/n
sin c= 1/1.33
sin c= 0.752
c= 48.8 degrees

Sambaddest

2 years ago

sin c=1/n
sin c=1/1.33
sin c= 0.752
c= sin^-1 0.752
c= 48 degrees
Now we can't perform sin inverse operation with the jamb calculator that's why youll have to know the basic degrees
sin30= 0.5
sin45= 0.71
sin60= 0.866
sin90=1
so looking at it 0.752 is in between sin45 to sin60
and from the option 48.8 is the only number btw those 45 to 60
therefore option D is correct
try to know the basic degrees both in surd and decimal form

Gordonsparks

3 years ago

how on Earth can we get sin-¹ in jamb calculator, the should stop this nonsense oh

Kingneezar9

2 years ago

like srsly why would a put a question that requires (sin)