What is the escape velocity of a satellite launched from the earth’s surface? (Take g as 10ms\(^{-2}\) and the radius of the earth as 6.4 × 10\(^6\)m)
7.80 × 10kms-1
11.2 × 10kms-1
3.56 × 107ms-1
6.00 × 107ms-1
1.20 × 108ms-1
Explanation
Video Explanation
No video available
Post your Contribution
Discussions (8)
To calculate the escape velocity of a satellite launched from the Earth's surface, we can use the formula for escape velocity:
Where:
-
is the escape velocity,
- is the acceleration due to gravity (approximately
),
- is the radius of the Earth (approximately
).
Now, let's plug in the values into the formula:
1. Substitute and :
2. Calculate the value inside the square root:
3. Now, take the square root:
4. Approximating the square root:
Therefore, the escape velocity for a satellite launched from the Earth's surface is approximately 11,313 m/s.
pls how can we solve this kind of question,you know the is no squareroot in jamb calculation .
