The energy stored in a capacitor of capacitance 5 μF is 40J. What is the voltage applied across its terminals?

a

4V

b

8V

c

16V

d

200V

e

4000V

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almubarak1
9 years ago

w=1/2CV²

40=1/2*5*10^-6*V²

V²=40/2.5*10^-6

V²=16,000000

V=√16,000000

V=40000

chichiuk
1 year ago

thanks that really helped

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