A transformer is connected to a 250 V a.c. supply. The primary coil has 5000 turns and the secondary voltage is found to be 10 V. What is the number of turns in the secondary coil?
To find the number of turns in the secondary coil of a transformer, we use the transformer equation:
\(\frac{V_p}{V_s} = \frac{N_p}{N_s}\)
Given:
\( V_p = 250 \, \text{V}\)
\( V_s = 10 \, \text{V} \)
\( N_p = 5000 \, \text{turns} \)
Rearranging the equation to find \( N_s \):
\(N_s = N_p \times \frac{V_s}{V_p}\)
Plugging in the values:
\(N_s = 5000 \times \frac{10}{250}\)
\(N_s = 5000 \times 0.04\)
\(N_s = 200 \, \text{turns}\)
Therefore, the number of turns in the secondary coil is 200.
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