Correct Answer: Option C

Explanation

To find the number of turns in the secondary coil of a transformer, we use the transformer equation:

\(\frac{V_p}{V_s} = \frac{N_p}{N_s}\)

Given:
 \( V_p = 250 \, \text{V}\)
 \( V_s = 10 \, \text{V} \)
  \( N_p = 5000 \, \text{turns} \)

Rearranging the equation to find \( N_s \):

\(N_s = N_p \times \frac{V_s}{V_p}\)

Plugging in the values:

\(N_s = 5000 \times \frac{10}{250}\)

\(N_s = 5000 \times 0.04\)

\(N_s = 200 \, \text{turns}\)

Therefore, the number of turns in the secondary coil is 200.

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