How much heat is required to convert 5.0g of ice at 0 ° C to water at the boiling point? (Specific latent heat of ice = 336Jg-1 specific heat capacity of water = 4.2Jg-1K-1)

DoctorStella

5 years ago

let U, represent change in theta
Q= mcU + ml...
where Q= quantity of heat, m= 5g, U= 100-0= 100, specific heat capacity of water (c)= 4.2Jg-1K-1, Specific latent heat of ice (l) = 336Jg-1
Q= 5*4.2*100 + 5*336
Q= 3780J

ademilekanjohn

9 years ago

Q=ML+MC(thetre)

frednard

3 months ago

no answer

peter samson

9 years ago

please explanation..