N.N.P.C. gas cylinder containing 15kg of cooking gas was left open, and the gas emptied in 3.8 minutes, at an average speed of 20 ms^-1. What force was exerted on the gas in the cylinder?

smartking12

2 years ago

recall F=ma
but a=v÷t
t=3.8×60=228 seconds
therefore F=15×20÷228=1.3157
approximately 1.32

Martinsjta

1 year ago

m=15kg
t=3.8, 3.8*60=228s
v=20ms^-¹
f=?
f=m(v_u)÷t
f=15(20_0)÷228
f228=300
f=300÷228
f=1.315
f=1.312N