A waterfall is 630m high. What is the change in temperature of a quantity of water that falls from the top to the bottom of the waterfall? (Neglect heat losses to the surroundings, take g as 10 ms-2 and specific heat capacity of weather as 4200J kg-1K-1
0.015°C
1.50°C
15.00°C
21.00 °C
50.00°C
Explanation
Video Explanation
No video available
Post your Contribution
Discussions (12)
Answer: 1.5°C
Using the water height as 630cm
Q=m*c*(02-01)
where; (02-01)=change in Temperature
Q
=Force*distance
=mass*acceleration*distance
=m*a*d
Q=m*c*(02-01)
m*a*d=m*c*(02-01)
cancel m from both sides
a*d=c*(02-01)
(02-01)=(a*d) / c
(02-01)=(10*630) / 4200
(02-01)=6300/4200=63/42
(02-01)=1.5°C (answer)
Therefore, the change in Temperature is 1.5°C
Note: If the water height was 63m, the temperature would be 0.15°C & if it was 6.3m, the temperature would be 0.015°C
The values aren't correct. Guess the 6.30m should be 630m then the answer can be 0.15
