What is the energy stored in a 10μ F capacitor if the potential difference between the plates is 40 V?

Vee.xxx

1 year ago

To find the energy stored in a capacitor, we use the formula:

𝐸 = 1/2 𝐶𝑉^2

where:
𝐸 is the energy stored in the capacitor,
𝐶 is the capacitance of the capacitor,
𝑉 is the potential difference between the plates.

Given:
𝐶 =10 𝜇F = 10 × 10 ^−6 F
𝑉 = 40V

Substituting the values:
𝐸 = 1/2 × 10 × 10^−6F × (40V)^2
𝐸 = 1/2 × 10 ^−5F × 1600V^2
𝐸 = 0.5 × 10^-5 × 1600
𝐸 = 0.5 × 0.016
𝐸 = 0.008J

PeulthaiJackO

3 years ago

Use the formula “Energy = 1/2 * CV^2”