What is the coefficient of static friction between a load of mass 2kg and a horizontal surface, if the limiting frictional force is 10N? (g = 10 ms^-2)

Davidtor

6 years ago

F=UR
But F=10N
U=mg=2×10=20
U=?
F=Umg
U=F/mg
U=10/20
U=0.5

luckyeshio

1 year ago

To find the coefficient of static friction (μs), we can use the formula:


μs = F / N


where:


- μs = coefficient of static friction
- F = limiting frictional force (10 N)
- N = normal force (equal to weight, mg)


First, calculate the normal force (N):


N = mg
= 2 kg × 10 m/s²
= 20 N


Now, calculate μs:


μs = F / N
= 10 N / 20 N
= 0.5


So, the coefficient of static friction between the load and the horizontal surface is:


μs = 0.5


This value indicates that the surface has a moderate level of friction, requiring a significant force to initiate movement.