A gas occupies a certain volume at 27°C. At what temperature will its volume be twice times the original volume assuming that its pressure remains constant?
\(\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}\)
Given \(V_{2} = 2V_{1}\)
\(T_{1} = 27°C + 273 = 300k\)
\(\frac{V_{1}}{300} = \frac{2V_{1}}{T_{2}}\)
\(\frac{1}{300} = \frac{2}{T_{2}} \implies T_{2} = 600k or 327°C\)
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