In the AC circuit diagram above, the resonance frequency is

Ismaildamilare2

7 years ago

For resonance frequency

Xl = Xc

Recall Xl = 2πfl

Xc = 1/2πfc

We have....

2πfl = 1/(2πfc)

(2πf)² = 1/lc

f² = 1/[(2π)²lc]


f = 1/2π_/1/lc

l = 8mH = 8*10-³H

C = 5*10^-6C

F = 1/2π_/[(1/(5*10^-5)(8*10^-3)]

F = 1/2π_/2.5*10^7

F = 5000/2π = 2500/π Hz.....

GeeRoyal09

2 years ago

f⁰=1/2π * √1/LC
{Capacitance,C=5 * 10^-6 ; Inductance,L= 8 * 10^-3}
1/2π * √1/(5*10^-6 × 8*10^-3)
=2500/π or 795.77Hz

zitababy

4 years ago

Thanks for ur contribution ,but can u minimze the soln

GeeRoyal09

2 years ago

The diagram was not given in the question

ugwubezaleel

3 years ago

use
F=1/(2pi√fC)
where F is resoance frequency
pi=22/7 or 3.142
f=inductance
C=capacitance