The total resistance measured at PQ in the diagram above is

Abike23

5 years ago

Solution:
The three 2 ohms are in series, therefore the total resistance is
R=R1+R2+R3
R=2+2+2= 6 ohms.
Redrawing the circuit:
6 ohms is used to replace the three 2 ohms which is therefore placed by the 3 ohms resistor.
The 3 ohms and 6 ohms resistors are in parallel, so the combined resistance is
R=R1R2/R1+R2
R=3×6/3+6
R=18/9=2 ohms.
Redrawing the circuit again:
The 2 ohms is used to replace the 3 ohms and 6 ohms laying side-by-side.
Therefore, the 3 resistors (1ohm, 1ohm and 2 ohms) are in series.
Thus, the total resistance is
R=R1+R2+R3
R=1+1+2=4 ohms.
Therefore, the total resistance measured at PQ is 4 ohms.

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