A uniform light beam XZ is Hinged at X and kept in equilibrium by the forces T and F as shown in the diagram above. if XO = 20cm and OY = 30cm, express T in terms of F

a

T =2√3/3

b

T= 2F

c

T = 5V3F/3

d

T = 5F

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Correct Option
d

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Discussions (9)

Aruehi
6 years ago

F × (20cm + 30cm) = T sin 30° × 20

50F = 10T

T = 50F/10
T = 5F.

AdeTunji2004
5 years ago

Sum of upward forces= sum of downward forces
Tsin30° × 20 = F × (20 + 30)
since sin 30 = 0.5
10T = 50F
T = 5F

christy1234
9 years ago

someone shuld pls explain

Arbjigdgbhkoinn
1 year ago

No answer

Anzyumoh
4 years ago

taking moment about x, why?

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