The fig above shows a block of mass m sliding down a rough inclined plane QP at angle \( \theta \) . The forces acting on the block along QP are
The weight mg acts vertically downward.
Along the incline (parallel to QP):
The component of weight down the plane: mg sinθ
Since the plane is rough and the block is sliding down, kinetic friction acts up the plane, opposing the motion.
The normal reaction (N) acts perpendicular to the plane (not along QP).
So, forces along QP (parallel to the incline) are:
1. mg sinθ (down the plane)
2. Force of friction (up the plane)
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