For what value of \(\theta\) are the forces in the diagram above in equilibrium
So the diagram in the question is compressed to the one above.
From the diagram: Cos\(\theta\) = \(\frac{6}{12}\) = \(\frac{1}{2}\)
\(\theta\) = Cos\(^{-1}\)(0.5) = 60º
Please don't post or ask to join a "Group" or "Whatsapp Group" as a comment. It will be deleted. To join or start a group, please click here
Contributions ({{ comment_count }})
Please wait...
Modal title
Report
Block User
{{ feedback_modal_data.title }}