For what value of \(\theta\) are the forces in the diagram above in equilibrium

wise357

4 years ago

Using Cosine rule:
Cos A=(b²+c²-a²)/2bc
=(12²+6²-(6√3)²)/(2×12×6)
=72/144
Cos A = 0.5
A= Cos–¹ 0.5
A=60°

Emmanuel24458

2 years ago

Simply use sohcahtoa
Sintita= opp/hyp
6√3÷12
0.866
Sin inverse=60

Cocos

7 years ago

explanation pls my school

P.Royalty

1 year ago

no explanation

frenchpie

2 years ago

please why have i stopped seeing diagrams and images in all my subjects (phy, chem, nd bio) on myschool? Is there anything i can do about it?
thank you

AdejoJoseph

4 years ago

explanation pls

kungfukenny

1 year ago

i need it solved