The acceleration of the system show above is

Bliss3

3 years ago

treat the motion of the two body independently;
Mg-T=Ma
T-mgsin∅=ma
So for 30kg we have
Mg-T=Ma
300-T=30a...equ 1
For 20kg we have
T-200×0.5=20a
T-100=20a...equ 2
ADD equ 1 and 2
300-T=30a
T-100=20a
-T+T=0 so they cancel out
300-(+100)=50a
200=50a
200/50=a
a=4

Tega204

2 years ago

F(net)= M(net) x a
a=F(net)/M(net)
M(net) = 20+30=50 kg
F(net)= m2g - m1gsin 30
F(net)= (30 x 10)- (20 x 10sin30 )= 200N
a=200/50=4m/s²

Emmdicare

2 years ago

m2g - m1gsinθ = ( m1 + m2)a
30 x 10 - 20 (10) sin30= (20 + 30)a
300 - 200 x 0.5 = 50a
300 - 100 = 50a
a = 200/50
∴ a = 4ms-2

ApexBrain

5 years ago

Please the diagram is so unclear......That is why i failed to get the answer...

Emmdicare

2 years ago

g

school40

1 year ago

i need the explanation for this question

heich

4 years ago

Please does anyone know how to get the answer?

♡ally》

3 weeks ago

I input a as the answer and later after submitting and failing the question seeing b as what I choosed