The fig above shows a uniform wood of weight 200Nand length 50m. It is pivoted at one end and suspended by a cord at the other end at an angle of 30 degrees to the wood. calculate the tension in the cord if the wood is horizontal

samare

4 years ago

reslove T into vertical componet :Tsin30
so tsin30 x 50 = 200 x 25
T=200N

GentyA

3 years ago

its a rod of 50cm and its uniform so half of the rod is 25cm with a weight of 200N. assume the rod is pivoted at p and suspended at q at 50cm. so calculate tension T in the cord: 200*25=Tsin30*50°; T=200*25/sin30°; 5000/0.5*50= 200N.
Note: sin30°= 1/2 or 0.5

Tayoadesalaam

4 years ago

tension = m*gravity where m equals to mass
so 200N%10=20grams
20*10=200N

ElonDee

1 year ago

I also don't understand this topic till now 😞

rajiummuani

11 months ago

No answer

MhizDee430

9 months ago

Easy formula.
Tsinø = Tsin∅
200 × sin 30 = T sin 30
200 × 0.5/0.5 = T
T = 200N

Aghede

11 months ago

explanation is not available

jambet

2 years ago

i dont know y i cant understand this topic and i heard is simple 🤌

King33Victor

3 months ago

why not resolving it into horizontal component cos30 since they said horizontal

regony600

9 years ago

T=W-F

T=200-200sin30

T=200-100=100N