In the fig above,A lever of length 200m is used to lift a load of mass 180kg. The pivot at P is 20m from the load. what minimum force F must be applied at the end of the lever [g = 10ms-2]

ThankGodNwaoha

7 years ago

MA=distance move by d efffort frm d fulcrum/distance move by the load frm d fulcrum
distance by load=20m
distance move by effort=200-20=180m
sotherfor,MA=180/20=9
for the minimum force(F)=?
MA=load/effort,where load=180x10=1800N
sotherefor,MA=1800/efort, whereMA=9

Effort=1800/9=200N

koleojo

2 years ago

Taking moments from P (pivot)
The distance between the pivot and the force F = 200-20 =180, while the distance between the load and point P is 20, we recall that total Anti clockwise moment =total clockwise moment and moment = force x perpendicular distance so we can therefore say 180xF =180 x 10 x 20,180F=36000, F=200N

daturchoco

1 year ago

there should be explanation because I paid for it