In the diagram above, the hanging mass \(m_2\) is adjusted until \(m_1\) is on the verge of sliding. The coefficient of static friction between the mass \(m_1\) and the table is

a

m1/m2

b

m1g/m2

c

m2/m1

d

m2g/m1

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Correct Option
c

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Discussions (5)

Ahmadi2020
3 years ago

M2g=uM1g=
u=M2g÷M1g=M2/M1

Dadaet2008
1 year ago

O can't see the diagram well enough

TeReTeRe
7 years ago

What is the difference between option C and D?

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