K is Opened
K is closed
the 14 ohm resistor is doubled with k closed
the 6 ohm resistor is doubled with k closed
Explanation
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If K is closed, current (I)=36/(14+6) =1.8A
If K is opened, I = 36/14 =2.57A
Thus, the Fuse wire will not melt when the key, K is closed since the circuit current (1.8A) is less than the Fuse rating (2A). The Fuse will melt only if the key is opened as this caused the current to increase to 2.57A which is greater than the Fuse rating.
Therefore the correct answer is A
A fuse melts when the current becomes too large (overload).
Use Ohm’s law:
Check each case
When K is open
Current flows through 14 Ω + 6 Ω (series).
Total resistance = 20 Ω
Current = � → smaller current (less likely to melt fuse).
When K is closed
The switch bypasses (short-circuits) the 6 Ω resistor.
Only 14 Ω remains in the circuit.
Total resistance decreases.
Current = � → larger current → fuse melts.
✅ Correct answer: B — K is closed
A is the correct answer because the current is greater then 2A when the key is opened, which will cause the fuse wire to melt.
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the one in jamb is wrong 14th feb 2001,which result due to implentation of NIN in jamb proces
but he use his real date if birth from his original birth certificate to register for unn postume
pls admin can these mistake hinder his admission succes...?
A is the correct answer because as k is opened the current= 36/14= 2.57
which is higher than the fuse rating hence kaboom😂
