Correct Answer: Option D

Explanation

Capacitance in parallel.

\(C_4 = C_1 + C_2\) = 2 + 2 = 4µf.

\(\frac{1}{C_T} = \frac{ 1}{C_3} + \frac{1}{C_4}\)

                        = \(\frac{ 1}{4} + \frac{1}{4}\)

                       = \(\frac{ 1 + 1}{4}\)

\(\frac{1}{C_T} = \frac{2}{4}\)

\(C_T = \frac{4}{2}\) = 2µf.

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