Correct Answer: Option B

Explanation

The diagram transforms into the one above:

Tan 30º = \(\frac{\text{opp}}{\text{adja}}\) = \(\frac{T_1}{100}\)

But tan 30º = \(\frac{1}{\sqrt{3}}\)

\(\frac{1}{\sqrt{3}}\) =  \(\frac{T_1}{100}\)

T\(_1\) = \(\frac{100}{\sqrt{3}}\)N

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