Correct Answer: Option B

Explanation

Since the resistors are in parallel, the p.d across them is the same, 

P = VI but I = \(\frac{ V}{R}\)

P =  \(\frac{ V^2}{R}\) = power dissipated by 5Ω resistor,

40 =   \(\frac{ V^2}{5}\)

\(V^2\) = 200V.

Power dissipated by the 10Ω resistor,

P =  \(\frac{ V^2}{R}\) =  \(\frac{200}{10}\)

 P = 20W.

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