In the diagram above, X and Y have resistances 6 and 4 ohms respectively, if the power dissipation in X is 10W then power dissipation in Y is
P = \(\frac{ V^2}{R}\)
\(P_1 R_1 = P_2 R_2\) ( Parallel circuit)
10 x 4 = \(P_2\) x 6
\(P_2\) = \(\frac{40}{6}\) = 6.7W.
Contributions ({{ comment_count }})
Please wait...
Modal title
Report
Block User
{{ feedback_modal_data.title }}