In the circuit Shown above, calculate the effective capacitance between X and Y

a

3/4µF

b

\( 2 \frac{10}{13} µF\)

c

12µF

d

\( 4 \frac{12}{13} µF\)

e

13µF

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Discussions (7)

Deepthinker581
4 years ago

The effective capacitance in parallel =4+3+4=9
The total effective capacitance would now be a series of 4 and 9
For that we have 1/C
1/4 and 1/9

4+9=13
4×9 =36
C=36/13
Which in solve would be 2(10)/3

Boluwa124456
2 years ago

the effective capacitance 4+3+2=9
the remaining capacitance is 9 and 4
9*4 ÷ 9+4
36/13

Debbypebby
4 years ago

I don't understand. @myschool please provide an explanation to this question.🙏

Gvhb
3 years ago

explanation

Johnson9944
1 year ago

th answer nor dey option the answer is supposed to be 6*6/13 or 36/13

olyezema
4 years ago

my school pls provide an explanation for this question

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