Correct Answer: Option E

Explanation

Current = \(\frac{\text{Voltage}}{\text{Resistance}}\)

I\(_1 = \frac{10}{2}\) = 5A

I\(_2 = \frac{10}{1}\) = 10A

I\(_3 = \frac{20}{3}\) = 6.67A

I\(_4 = \frac{20}{2}\) = 10A

I\(_5 = \frac{20}{1}\) = 20A

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