The value of the series resistor required to convert the above galvanometer into a voltmeter with a full range deflection of 15V is

Odisontech

3 years ago

Here's my solution
using
I=V/r+R
where I=0.015A,r=5,R=?
R=V-ir/I
=15-0.015*5/0.015
=14.925/0.015
R=995

koleojo

2 years ago

official solution here
v=v+v
v=1(R+r)
15=0.015(R+5)
15=0.015xR +0.015x5
15=0.015R + 0.075
15-0.075=0.015R
14.925/0.015 =R

nafisahoziohu

1 year ago

why there's no explanation for this question

Rodrigueiz

5 years ago

The correct answer is A(985 ohms)
Explanation:
Using:
Rm= V/I -Rg
Where v=15
I= 0.015
Rg= 15
Rm= 15/0.015 -15
Rm= 985 ohms

Tazer

1 year ago

R =V/Ig
R = (15/0.015)-5
R =1000-5
R = 995ohms
the correct answer is C