What is the acceleration of a particle whose motion is graphically displayed in the diagram above
0.67ms-2
0.83ms-2
0.87ms-2
92ms-2
2.0ms-2
Explanation
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Discussions (26)
Acceleration=The slope of the graph
Acceleration (a)=∆V/∆t
a=(8.7-2)/10. =0.67ms`²
accelerate is equal to the slope of the graphed which is m
m = ∆velocity\∆time
= (8-2)ms-¹\(9-0)s
= 6ms-¹\9s
= 0.67ms-²
I didn't see the diagram.
Pls My school should try to correct this. there are some questions that require diagram but there diagram is not given in the question
wtf is this
this diagram is not accurate
I would have gotten all if not for this
a=v-u/t
a=8.7-2/10
a=0.67
v is above 8 and below 9 from the graph so I chose 8.7 hence that value
It is difficult to determine the acceleration with the manner in which this diagram is drawn
The formula for acceleration is v/t i.e
8/10 which will give you 0.8 and when you approximate option A your answer is 0.8
