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What is the total resistance in the above diagram?

Physics
JAMB 1980

What is the total resistance in the above diagram?

  • A. 5 ohms
  • B. 15 ohms
  • C. 25 ohms
  • D. 35 ohms
  • E. 45 ohms
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Correct Answer: Option C
Explanation

Resistance in series will be given as R = 10+10 → 20

Resistance in parallel will be given as \(\frac{1}{R}\) = \(\frac{1}{10}\) + \(\frac{1}{10}\) 

\(\frac{1}{R}\) =  \(\frac{2}{10}\) → \(\frac{1}{R}\) = \(\frac{1}{5}\)

Resistance in parallel = 5

Total resistance = 20 + 5 → 25ohms


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Post-UTME Past Questions - Original materials are available here - Download PDF for your school of choice + 1 year SMS alerts
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WAEC May/June 2024 - Practice for Objective & Theory - From 1988 till date, download app now - 99995
WAEC offline past questions - with all answers and explanations in one app - Download for free
WAEC Past Questions, Objective & Theory, Study 100% offline, Download app now - 24709
WAEC May/June 2024 - Practice for Objective & Theory - From 1988 till date, download app now - 99995
Post-UTME Past Questions - Original materials are available here - Download PDF for your school of choice + 1 year SMS alerts