fig 12 shows the velocity time graph of a car which starts from rest and is accelerated uniformly at the rate of 3m sec^-2 for 5 seconds. It attains a velocity which is maintained for a minute, The car is then brought to rest by a uniform retardation after another 3 seconds. calculate the total distance covered

Olujosh

9 years ago

a=(v-u)/t, u=0,

v= 5×3= 15m/s

Total D = area of shape

d= 1/2(15)(5) + 60×15 + 1/2(15)(3)

= 960m.

vikky2244

1 year ago

60sec +5 sec+3 sec

BOSSALEX

3 years ago

u seriously don't understand

NNAEMEKAPROMISE

1 year ago

how did you get the 68

Spakfire 🔥🔥

8 months ago

In the velocity- time graph, the first time is 5s, the uniform velocity is attained at 60s but we don't just put 60s in the graph like that we will add it to five and then lastly to 3 so that the graph will show full time for the motion. Thanks