In a resonance tube experiment, which is illustrated above, the velocity of sound in air is 327.68m/s, the frequency of the turning fork used is therefore?

Giuseppe.Jose

9 years ago

Here is an explanation:

The diagram given in the question is a closed pipe.

for close pipes, the frequency is given as F=nv/4l while for opened pipes it is f=nv/2l

the number of harmonics,n is 1. Which is the fundamental note.

v is the speed of sound(it was given).

l is the length in meter(it was given)

substituting the values;

f=nv/4l

f=1 X 327.68 /4 X 0.16

f=327.68/0.64

f=512HZ

note that the length was converted from centimeters to meters.



HOPE THIS HELPS. ;)

Destinedtowin

4 years ago

here is a solution
parameters given V=327.68,L=16cm=>0.16m,f=?
wavelength= 4L
=>4*0.16=0.64 is the wavelength
let recall,
Velocity=Frequency*wavelenght
we are told to look for frequency
make frequency the subject formular
=>Frequency=velecity/wavelength
327.68/0.64
=>521Hz

jaycobfayvour

1 year ago

how do I know if it's an open or a closed pipe

ADETUTUADESEWA

3 years ago

no explanations for the free cbt