An air column 10cm in length is trapped into the sea end of a capillary tube by a 15cm column of mercury with the tube held vertically as shown above. On inverting the tube the air column becomes 15cm long. The atmospheric pressure during the experiment is

DeSurgeon

5 years ago

my second please rectify your answer it's supposed to be C which is 75..

this is it , when it's was vertical the Gas pressure was (H+15)

since the length of air makes the volume , VI =10cm

when it's was now inverted Gas pressure 2 was now (H-15)

and V2=15cm

relating to boyles law where Pressure directly prop to the reciprocal of Volume 1/V

Vp=Vp

10(H+15)=15(H-15)

10H+150=15H-225

150+225=15H-10H

H=375/5

H=75

TEAM SPM.

Sammyporsche123

3 years ago

My school how many years.
You've not still changed it to 75

T3mzie

2 years ago

P1L1=P3L3
(A+H)L1=(A-H)L3
(A+15)10= (A-15)15
10A+150=15A-225
15A-10A=225+150
5A=375
A=375/5 =75cm option C

Chiefdoc100

1 year ago

just seen my Jamb result for the 2025 UTME. my sleepless night paid

328, medicine incoming

Chidimmchibuike

5 years ago

D answer should be c not b

Efranklyn

4 years ago

The answer is C a well detailed solution from Surgeon

Kenhinde

4 years ago

Wow,thank you Lord,I just guess the answer,And my school still missed for me

Chi4sure

2 years ago

P1=(H+15),
V1=10A
P2=(H−15),
V2=15A
(p+15)10=(p−15)15
The atmospheric pressure
p=75 cm of Hg=750 mm of Hg

Deepthinker581

4 years ago

15×15=225
15×10=150

225-150=75

DeborahCyril

6 years ago

Acceleration=v^2 -u^2 ÷time (t)
Ie 2^2-0^2÷6=
4÷6=0.66~0.67